6/x^2-5x-4/x=2/x-5

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Solution for 6/x^2-5x-4/x=2/x-5 equation:


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

6/(x^2)-(5*x)-(4/x) = 2/x-5 // - 2/x-5

6/(x^2)-(5*x)-(4/x)-(2/x)+5 = 0

6/(x^2)-5*x-4*x^-1-2*x^-1+5 = 0

6*x^-2-5*x^1-6*x^-1+5*x^0 = 0

(5*x^2-5*x^3-6*x^1+6*x^0)/(x^2) = 0 // * x^4

x^2*(5*x^2-5*x^3-6*x^1+6*x^0) = 0

x^2

5*x^2-5*x^3-6*x+6 = 0

{ 1, -1, 2, -2, 3, -3, 6, -6 }

1

x = 1

5*x^2-5*x^3-6*x+6 = 0

1

x-1

-5*x^2-6

5*x^2-5*x^3-6*x+6

x-1

5*x^3-5*x^2

6-6*x

6*x-6

0

-5*x^2-6 = 0

DELTA = 0^2-(-6*(-5)*4)

DELTA = -120

DELTA < 0

x in { 1}

x = 1

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